Complying with standard C

Second example: result is the same

In the following code, assume that both unsigned short and unsigned char are narrower than int.

   int f(void)
   {
       unsigned short us;
       unsigned char uc;
   
       return uc < us;
   }

In this example, both automatics are either promoted to int or to unsigned int, so the comparison is sometimes unsigned and sometimes signed. However, the ANSI C compiler will not warn you because the result is the same for the two choices.